This is called normal distribution. First we must find Z, to get z we do (X=6 here), (x-mean)/s.dev. so 6-5/0.7. This get 1.428. Now we use our table to get the probability of Z happening. This number is 0.9236. However this gives us the probability of P(Z{6). We want P(Z}6) so we do 1-0.9236, which gets us 0.0764.