Respuesta :
Assume two numbers, x and y
x + y = 15
xy = 50
y = 15 - x
x(15-x) = 50
15x- x^2 = 50
x^2 - 15x + 50 = 0
(x-5)(x-10) = 0
either
x = 5 -> y = 10
or
x = 10 -> y = 5
The two numbers are 10, 5
x + y = 15
xy = 50
y = 15 - x
x(15-x) = 50
15x- x^2 = 50
x^2 - 15x + 50 = 0
(x-5)(x-10) = 0
either
x = 5 -> y = 10
or
x = 10 -> y = 5
The two numbers are 10, 5
Let, the numbers = a, b
Then, a + b = 15
a * b = 50
Substitute the value of a from equation (1),
(15-b) * b= 50
15b - b² = 50
b²-15b+50 = 0
b²-5b-10b+50 = 0
b(b-5) -10(b-5) = 0
(b-5)(b-10) = 0
b = 5 OR 10
In short, Your Numbers would be: 5 & 10
Hope this helps!
Then, a + b = 15
a * b = 50
Substitute the value of a from equation (1),
(15-b) * b= 50
15b - b² = 50
b²-15b+50 = 0
b²-5b-10b+50 = 0
b(b-5) -10(b-5) = 0
(b-5)(b-10) = 0
b = 5 OR 10
In short, Your Numbers would be: 5 & 10
Hope this helps!