In order to solve for this, we need to find the volumes of both the cylinder and cone described.
In order to find the area of the cylinder:
We use the equation V=[tex]\pi r^{2} h[/tex]
So, V=[tex]\pi 6^{2}16[/tex]
The volume of the cylinder is therefore approximately 1809.56[tex]m^{3}[/tex]
For the cone:
V=[tex]\pi r^{2} \frac{h}{3}[/tex]
So, V=[tex]\pi 6^{2} \frac{3}{3}[/tex]
Thus, the volume of the cone is 113.1[tex]m^{3}[/tex]
We add these volumes together to derive the solution, which is 1922.66[tex] m^{3} [/tex]
