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What is the area of a sector with a central angle of 160 degrees and a diameter of 5.8 m?

Respuesta :

Diameter=5.8
Radius= 2.9

Area= 2.9*2.9*pi=8.41pi

8.41pi*160/360~11.74

Answer: 11.7 sq. m.

Step-by-step explanation:

The area of sector with angle x and radius r is given by :-

[tex]\text{Area of sector}=\frac{x}{360^{\circ}}\pi r^2[/tex]

Given: Diameter = 5.8 m

Then, radius =[tex]\frac{5.8}{2}=2.9\ m[/tex]

Now, the area of sector with angle 160° and radius 2.9 is given by :-

[tex]\text{Area of sector}=\frac{160^{\circ}}{360^{\circ}}\pi (2.9)^2\\\\\Rightarrow\ \text{Area of sector}=\frac{160{\circ}}{360^{\circ}}(3.14)(2.9)^2\\\\\Rightarrow\ \text{Area of sector}=11.7366222222\approx 11.7\ m^2[/tex]