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Which equation represents a circle with a center at (2, –8) and a radius of 11?

A.(x – 8)2 + (y + 2)2 = 11
B.(x – 2)² + (y + 8)² = 121
C.(x + 2)² + (y – 8)² = 11
D.(x + 8)² + (y – 2)² = 121

Respuesta :

apologiabiology
the eqation with center at (h,k) and having a radius of r is
(x-h)²+(y-k)²=r²

given
cetner is (2,-8) and radius is 11

(x-2)²+(y-(-8))²=11²
(x-2)²+(y+8)²=121

B is answer
abidemiokin

The equation represents a circle with a center at (2, –8) and a radius of 11 is (x - 2)² + (y +8)² = 121

The standard equation of a circle is expressed as;

(x - a)² + (y – b)² = r²

where:

(a, b) is the centre of the circle

r is the radius of the circle'

Given the following

  • a = 2
  • b = -8
  • r = 11

Substitute into the formula to have:

(x - 2)² + (y – (-8))² = 11²

(x - 2)² + (y +8)² = 121

Hence the equation represents a circle with a center at (2, –8) and a radius of 11 is (x - 2)² + (y +8)² = 121

Learn more on equation of a circle here: https://brainly.com/question/14150470

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