At a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. The inner edge of the sidewalk is a circle with a radius of 9 m.



(A)Write and simplify an expression for the exact area of the sidewalk.
(B)Find the approximate area of the sidewalk. Use 3.14 to approximate π.
Answer:

At a zoo the lion pen has a ringshaped sidewalk around it The outer edge of the sidewalk is a circle with a radius of 11 m The inner edge of the sidewalk is a c class=

Respuesta :

Let R be the greater radius and r be the smaller radius

A) Area of the sidewalk = [tex] \pi [/tex]R^2 - [tex] \pi [/tex]r^2   - This can be the expression

B) [tex] \pi [/tex] = 3.14
=[tex] \pi [/tex](R^2-r^2)
=[tex] \pi [/tex](11^2-9^2)
=[tex] \pi [/tex](121-81)
=[tex] \pi [/tex]*40

That was the simplified expression

Answer = 3.14 * 40 = 125.6m^2

The expression for the exact area of the sidewalk is area = π(11² - 9²). And the approximate area of the sidewalk will be 125.6 m².

What is a circle?

It is a locus of a point drawn an equidistant from the center. The distance from the center to the circumference is called the radius of the circle.

At a zoo, the lion pen has a ring-shaped sidewalk around it.

The outer edge of the sidewalk is a circle with a radius of 11 m.

The inner edge of the sidewalk is a circle with a radius of 9 m.

The expression for the exact area of the sidewalk will be

[tex]\rm Area = \pi (r_o^2-r_i^2)[/tex]

We have

[tex]\rm r_o = 11 \ m\\\\r_i \ = 9 \ m[/tex]

Then the approximate area of the sidewalk will be

[tex]\rm Area = \pi (11^2-9^2)\\\\Area = \pi (121 - 81)\\\\Area = \pi (40)\\\\Area = 40 \pi = 125.6 \ m^2[/tex]

More about the circle link is given below.

https://brainly.com/question/11833983