makanafranzmann
contestada

n a certain plant species, the allele for wrinkled seeds (W) is dominant to the allele for smooth seeds. What is the phenotype result of a cross between a true-breeding wrinkle-seeded group of plants and a true-breeding smooth-seeded group of plants? A. 1/4 wrinkled seeds, 3/4 smooth seeds B. all smooth seeds, no wrinkled seeds C. 1/4 smooth seeds, 3/4 wrinkled seeds D. all wrinkled seeds, no smooth seeds

Respuesta :

20knishkaca
Make a punnet square

W W
w Ww Ww

w Ww. Ww



All wrinkled seeds, no smooth seeds but they are all carriers for the smooth gene
Genotype of Pure Wrinkled seeds = WW
Genotype of Pure Smooth Seeds = ww

Cross:  WW  * ww

Offspring:  Ww, Ww, Ww, Ww, 

Since, W is dominant over w, it will affect it's trait. So, All Offspring would be Wrinkled seeds.

In short, Your Answer would be: Option D

Hope this helps!

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