Answer: Option (D) is the correct answer.
Explanation:
It is given that pressure is constant and the given data is as follows.
[tex]V_{1}[/tex] = 492 mL, [tex]T_{1}[/tex] = 31 + 273 = 304 K
[tex]V_{2}[/tex] = 876 mL, [tex]T_{2}[/tex] = ?
Therefore, calculate the temperature [tex]T_{2}[/tex] as follows.
[tex]\frac{PV_{1}}{T_{1}} = \frac{PV_{2}}{T_{2}}[/tex]
Since pressure is constant so, value of P = 1.
[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]
[tex]T_{2} = \frac{V_{2}T_{1}}{V_{1}}[/tex]
= [tex]\frac{876 mL \times 304 K}{492 mL}[/tex]
= 541.268 K
= 541 K (approx)
Thus, we can conclude that value of [tex]T_{2}[/tex] is 541 K.
