Respuesta :
Answer: d. 0.10
Explanation: Mole fraction of a substance is the ratio of the moles of that substance to the total number of moles present.
[tex]{\text {mole fraction of glucose}}=\frac{\text{moles of glucose}}{\text {moles of glucose + moles of water}}[/tex]
[tex]Moles=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Thus [tex]{\text{moles of glucose}}=\frac{180g}{180g/mol}=1mol[/tex]
[tex]{\text{moles of water}}=\frac{162g}{18g/mol}=9mol[/tex]
[tex]{\text {mole fraction of glucose}=\frac{1}{1+9}=\frac{1}{10}=0.10[/tex]
Answer:
d. 0.10
Explanation:
So, according to definition of mole fraction:
[tex]Mole\ fraction\ of\ glucose=\frac {n_{glucose}}{n_{glucose}+n_{water}}[/tex]
Given,
Mass of glucose = 180 g
Molar mass of glucose = 180 g/mol
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]Moles= \frac{180\ g}{180\ g/mol}[/tex]
[tex]Moles_{glucose}= 1\ mol[/tex]
Given,
Mass of water = 162 g
Molar mass of water = 18 g/mol
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]Moles= \frac{162\ g}{18\ g/mol}[/tex]
[tex]Moles_{water}= 9\ mol[/tex]
Applying in the expression for mole fraction as:-
[tex]Mole\ fraction\ of\ glucose=\frac {n_{glucose}}{n_{glucose}+n_{water}}[/tex]
[tex]Mole\ fraction\ of\ glucose=\frac {1}{1+9}=0.10[/tex]
Correct answer is:- d. 0.10
