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The equation h(t)=−16t2+70t+40 gives the height of a toy rocket, in feet, t seconds after it is launched from a platform.

What is the height of the platform?

Enter your answer in the box.

_____ ft

Respuesta :

h(t)=−16t2+70t+40 gives the height of a toy rocket
height of the platform is equal to h(t) when t = 0
h(0) = 40 feet

Answer:

The height of the platform is 40 ft

Step-by-step explanation:

Given the equation:

[tex]h(t) = -16t^2+70t+40[/tex]         ....[1]

where

h(t) gives the height of a toy rocket in feet and

t is the time in sec after it is launched from a platform.

At platform:

t = 0

We have to find the height of the platform;

Substitute t=0 in [1] we have;

[tex]h(0) = -16(0)^2+70(0)+40[/tex]  

Simplify:

[tex]h(0) = 40[/tex] ft

therefore, the height of the platform is 40 ft

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