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In two or more complete sentences, describe how to graph each of the following equations. In your description, include the slope and both the x- and y-intercepts of each line. 1.Y=2. 2.y=-1/2x. 3.x-y=4. 4.x=-1

Respuesta :

1. y = 2.....this is a horizontal line
    y int = (0,2).....no x int because it never crosses the x axis
    slope for a horizontal line = 0
     So start at (0,2)...draw ur line straight across (horizontal)...y will always be     2 no matter what x is.

2. y = -1/2x
    y int = (0,0)......x int = (0,0).....slope = -1/2
    so,basically,start at (0,0).....go down one space,and to the right 2 spaces,       then down 1, and to the right 2...keep doing this and u will see ur line. And     if u need more points....sub in any number for x in ur equation, and solve      for y

3. x - y = 4.....y = x - 4
    y int = (0,-4)....x int = (4,0).....slope = 1
    start at (0,-4)....and since slope is 1, go up 1, and to the right 1, repeat....u     should cross the x axis at (4,0)

4. x = -1.....this is a vertical line
     no y axis because it never crosses y axis.....x axis = (-1,0)
     slope of a vertical line is undefined. So start at (-1,0), and ur line will be straight up and down....x will always be -1, no matter what y is.
    

The graph of the lines is as shown in following figure.

1) for line y = 2

slope = 0

x-intercept = 0

y-intercept = 2

2) for line  [tex]y=-\frac{1}{2}x[/tex]

slope = [tex]-\frac{1}{2}[/tex]

x-intercept = 0

y-intercept = 0

3) for line x - y = 4

slope = 1

x-intercept = 4

y-intercept = -4

4) for line x = -1

slope = undefined

x-intercept = -1

y-intercept = 0

What is the graph?

"It is the set of points which makes the equation true."

What is slope-intercept form of a line?

The slope-intercept form of a line is, y = mx + c

where m is the slope and c is the y-intercept

What is x-intercept?

"The point at which the graph of a function intersects the x-axis."

What is y-intercept?

"The point at which the graph of the function intersects the y-axis."

For given question,

Consider a line

1) y = 2

The graph of the line y = 2 is the straight line passing through point (0, 2) and parallel to x-axis.

If we compare above equation of line with slope-intercept form,

We have m = 0 and c = 2

This means for the line y = 2,

slope = 0

x-intercept = 0

y-intercept = 2

2) [tex]y=-\frac{1}{2}x[/tex]

The graph of the line  [tex]y=-\frac{1}{2}x[/tex] is the straight line passing through origin with slope m = -1/2.

Since the slope of the line is negative, it passes through the second and fourth quadrant.

If we compare above equation of line with slope-intercept form,

We have m = -1/2 and c = 0

This means for the line  [tex]y=-\frac{1}{2}x[/tex],

slope = [tex]-\frac{1}{2}[/tex]

x-intercept = 0

y-intercept = 0

3) x - y = 4

We write it above equation in slope-intercept form of line.

⇒ x - y = 4

⇒ -y = 4 - x

⇒ (-1) × (-y) = (-1) × (4 - x)

⇒ y = x - 4                          .........................(a)

For x = 0,

y = -4

and for y = 0,

x = 4

The graph of the line x - y = 4 is the straight line passing through points (0, -4) and (4, 0)

If we compare equation (a) with slope-intercept form,

We have m = 1 and c = -4

This means for the line x - y = 4,

slope = 1

x-intercept = 4

y-intercept = -4

4) x = -1

The graph of the line x = -1 is the straight line passing through point (-1, 0) and parallel to y-axis.

We know, the slope of a line parallel to the y-axis is undefined.

This means for the line x = -1,

slope = undefined

x-intercept = -1

y-intercept = 0

Therefore, the graph of the lines is as shown in following figure.

1) for line y = 2

slope = 0

x-intercept = 0

y-intercept = 2

2) for line  [tex]y=-\frac{1}{2}x[/tex]

slope = [tex]-\frac{1}{2}[/tex]

x-intercept = 0

y-intercept = 0

3) for line x - y = 4

slope = 1

x-intercept = 4

y-intercept = -4

4) for line x = -1

slope = undefined

x-intercept = -1

y-intercept = 0

Learn more about the slope and intercept of the line here:

https://brainly.com/question/12763756

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