Respuesta :
f(x) = 3x + 11
Is the function used to show this.
when you know this, you are able to do the following:
f(10) = 30 + 11 = $41
That would be the allowance of the 10th week.
The question, however wants the total.
This again, can be done like this:
f(1) + f(2) + f(3) + f(4) + f(5) + f(6) + f(7) + f(8) + f(9) + f(10) = $275 :)
14 + 17 + 20 + 23 + 26 + 29 + 32 + 35 + 38 + 41 = $275
Sure there is a better formula, but i couldnt seem to make it, sorry.
HUGE UPDATE: The sum is $275 not 200..
Is the function used to show this.
when you know this, you are able to do the following:
f(10) = 30 + 11 = $41
That would be the allowance of the 10th week.
The question, however wants the total.
This again, can be done like this:
f(1) + f(2) + f(3) + f(4) + f(5) + f(6) + f(7) + f(8) + f(9) + f(10) = $275 :)
14 + 17 + 20 + 23 + 26 + 29 + 32 + 35 + 38 + 41 = $275
Sure there is a better formula, but i couldnt seem to make it, sorry.
HUGE UPDATE: The sum is $275 not 200..
Answer: $275
Step-by-step explanation:
Given : Andrew earns an allowance of $14 the first week, $17 the next week, $20 the following week, and so on.
We can see that each week there is his allowance is increasing by $3.
That means his allowance is increasing Arithmetically.
We know that for Arithmetic sequence , the sum of first n terms is given by :-
[tex]S_n=\dfrac{n}{2}(2a+(n-1)d)[/tex]
, where a = First term
d= common difference
For the given situation, a = $14 and d=$3
Then, for n= 10 , we have
[tex]S_n=\dfrac{10}{2}(2(14)+(10-1)3)=(5)(55)=275[/tex]
Hence, Andrew will earn $275 over the course of 10 weeks.