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A container holds 15 pennies, 8 nickels, and 10 dimes. You will randomly select two coins without replacement.
Fill in the probabilities on a tree diagram.
How many ways can you select the coins?
How many ways can you select exactly 1 nickel?
What is the probability that you select 2 pennies?
What is the probability that you select a dime and then a penny?

Respuesta :

Grlxo
PART A:
.................. / P (14/32)
... P (15/33) - N (8/32)
.,/ .............. \ D (10/32)
./
/ ............... / P(15/32)
|--- N (8/33) - N (7/32)
\ ............... \ D (10/32)
.\
..\ .............. / P(15/32)
... D (10/33) - N (8/32)
.................. \ D (9/32)

PART B:
1) There are 9 possible outcomes (3 choices for first coin, 3 choices for second coin --> 3 x 3 = 9)

2) There are 4 outcomes with exactly 1 nickel {PN, NP, ND, DN}

3) PP --> 15/33 x 14/32
= 5/11 x 7/16
= 35/176

4) DP --> 10/33 x 15/32
= (10x15) / (33x32)
= (5x5) / (11x16)
= 25/176

*from another source*

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