At maximum speed an airplane travels 2100 miles against the wind in 6hrs. Flying with the wind the plane can travel the same distance in 4hrs

Respuesta :

Let, the speed of Airplane = x
Speed of Wind = y

We know, Speed = Distance / Time

So, x-y = 2100 / 6
x-y = 350
& x+y = 2100/4
x+y = 525

Substitute value of x from equation 1 into 2, 
350+y+y = 525
2y = 525-350
y = 175/2
y = 87.5

& x = 350+y = 437.5

In short, Speed of Airplane is 437.5 mph and Wind is 87.5 mph

Hope this helps!

The speed of the airplane is 437.5 mph and the speed of the wind is 87.5 mph.

What is the speed of an object?

The speed of an object can be defined by the ratio of the distance covered by the object to the total time to cover that distance.

Speed = Distance / Time

Let, the speed of the airplane = A miles / hour

The speed of the wind = B miles / hour.

Given, the total distance is = 2100 miles.

Time taken by the airplane against the wind is 6 hours.

Time taken by the airplane with the wind is 4 hours.

Therefore, (A - B) = 2100 / 6                    

⇒ (A - B) = 350                                      (1)

Again, (A + B) = 2100 / 4

⇒ A + B = 525                                        (2)

Adding equation (1) and equation (2), we get:

⇒ (A - B + A + B) = (350 + 525)

⇒ 2A = 875

⇒ A = 437.5

Putting the value of 'A' in equation (2), we get:

⇒ 437.5 + B = 525  

⇒ B = 525 - 437.5

⇒ B = 87.5  

Therefore, the speed of the airplane is 437.5 mph and the speed of the wind is 87.5 mph.

Learn more about speed of an object here: https://brainly.com/question/7642982

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