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For Jacob's birthday, a basketball is wrapped in wrapping paper with no overlaps. The ball has a volume of 288π in3. What is the area of the wrapping paper (in terms of π)?

Respuesta :

Haitianqueen
288π×3=2714.33605 hope this helps
to find the area of the wrapping paper you have to find the serface area of the ball 
you have the volume so you have to find the raduis using the formula
r=3(v/4pi)^1/3
r=3(288pi/4pi)^1/3
r=3(72)^1/3
r=216^1/3
r=6
then the surface area of the sphere
SA=4pi x r^2
SA=4pi x 6^2
SA=4pi x 36
SA=144pi

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