Respuesta :
[tex]KI (s) ----\ \textgreater \ K(s) + I_2 (g)[/tex]
Now, balance the equation:
[tex]2KI (s) ----\ \textgreater \ 2K(s) + I_2 (g)[/tex]
[tex]I_2 [/tex] in gaseous state exist as a diatomic molecule.
Now, balance the equation:
[tex]2KI (s) ----\ \textgreater \ 2K(s) + I_2 (g)[/tex]
[tex]I_2 [/tex] in gaseous state exist as a diatomic molecule.
The balanced equation for the reaction would be: [tex]2KI (s) ---> I_2 (g) + 2K (s)[/tex]
Decomposition
Potassium iodide (solid) goes by the chemical formula KI (s).
Iodine gas is a diatomic molecule with the formula I2 (g).
Solid potassium goes by the formula K (s).
Thus, an amount of solid potassium iodide decomposing into iodine gas and solid potassium can be represented by the balanced equation below;
[tex]2KI (s) ---> I_2 (g) + 2K (s)[/tex]
More on balancing chemical equations can be found here: https://brainly.com/question/8062886