The answer to the question is ≥28 N i.e the maximum frictional force of the surface acting on the object is greater than equal to 28 newton.
CALCULATION:
As per the question, the coefficient of static friction is given as 0.35.
Hence, the coefficient of static friction [tex]\mu=\ 0.35[/tex]
The normal force is given as 80 N.
Hence, the normal force F = 80 N.
We are asked to calculate the maximum frictional force of the surface exerted on the object.
The frictional force of the surface is equal to the product of coefficient of static friction with the normal reaction.
Mathematically frictional force f = [tex]\mu N[/tex]
= [tex]0.35\times 80\ N[/tex]
= 28 N.
Maximum frictional force is the product of coefficient of limiting friction with normal force .
If the coefficient of static friction given in the question corresponds to limiting friction, then the answer is 28 N.
If it is smaller than coefficient of limiting friction, then the maximum frictional force is greater than 28 N.
