Answer with explanation:
Sample Size (n)=72
→P=% of people who listen to radio while they are at work =16 %
→B=1 - P= 100% - 16% =84%
→Standard Deviation when Probability and Sample Size is given
[tex]\sigma=\sqrt{\frac{P(1-P)}{n}}\\\\ \sigma =\sqrt{\frac{\frac{16}{100} \times \frac{84}{100}}{72}}\\\\ \sigma=\sqrt{\frac{1344}{720,000}}\\\\\sigma=\sqrt{\frac{18.66}{10000}}\\\\\sigma=\frac{4.320}{100}\\\\ \sigma=0.0432[/tex]
So, standard deviation of the sampling distribution of the proportion for the sample of size 72= 0.0432=0.043 (Approx)
