Erinarissyer Erinarissyer

09-04-2017
Mathematics

contestada

Which expression is equivalent to b^m•b^n
A. b^m-n
B. b^m•n
C. b^m÷n
D. b^m+n

Respuesta :

09-04-2017

[tex]\displaystyle\\ \bold{b^m \times b^n = b^{m + n}~~~(D)}\\\\ \bold{\frac{b^m}{b^n}= b^{m - n}~~~~~~~~~(A)}\\\\ \bold{\Big(b^m \Big)^n = b^{m\times n}~~~~(B)}\\\\ \bold{\sqrt[\bold{n}]{\bold{b^m}} = b^{m\div n } ~~~~~~(C)}[/tex]

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