A player pays $1 to play a game where three fair dice are rolled. If three 6s are obtained the player wins $500, and otherwise thr pkayer wins nothing. What are the expected net winnings of this game?
Ans: $1.31
(I need a solution!)

The chance to win = 1 : 6³ = 1 / 216

To win $500, the player needs to pay $216 on average.
500/ 216 = 2.31
$2.31 win and $1 cost per game gives $1.31 net win.

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varshamittal029 varshamittal029 · Answer 2 · 2022-07-08T00:59:19+02:00

The expected net winning of the player is $1.31.

What is Probability?

Probability is the possibility of the occurrence of a particular event or the ratio of the number of outcomes favorable to event to the number of total outcomes.

The total number of outcomes if we rolled n dice is [tex]=6^n[/tex]

In this problem, the total number of outcomes if we rolled three dice [tex]=6^3=216[/tex].

In this outcome, only one involves all three 6s.

So the probability to get all three 6s = 1/216

Give that player wins $500 if player got three 6s

Hence winnings = 500*(1/216) = 2.31 (approximately)

He has to pay $1 to play.

So the net winnings is = $(2.31-1) = $1.31

Learn more about Probability here -

https://brainly.com/question/24756209

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A player pays $1 to play a game where three fair dice are rolled. If three 6s are obtained the player wins $500, and otherwise thr pkayer wins nothing. What are the expected net winnings of this game? Ans: $1.31 (I need a solution!)

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What is Probability?

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A player pays $1 to play a game where three fair dice are rolled. If three 6s are obtained the player wins $500, and otherwise thr pkayer wins nothing. What are the expected net winnings of this game?
Ans: $1.31
(I need a solution!)