Respuesta :

Photon
Hello there,

You should know the solubility of AgNO3 in water at 20°C equals to 2220 g/L.

So we can say that in 1 L of water, 2220 g of AgNO3 can be dissolve.

Now you should know 1L = 1000g.

Which means 1000 g of water can dissolve 2220 g of AgNO3.

Therefore :

250 g --> x
1000 g --> 2220 g

So : 
[tex]x = \frac{250*2220}{1000} = \frac{555000}{1000}= 555g [/tex].

In short, 555g of AgNO3 can be dissolved in 250g of water at 20°C.

Hope this helps !

Photon