Hello there,
You should know the solubility of AgNO3 in water at 20°C equals to 2220 g/L.
So we can say that in 1 L of water, 2220 g of AgNO3 can be dissolve.
Now you should know 1L = 1000g.
Which means 1000 g of water can dissolve 2220 g of AgNO3.
Therefore :
250 g --> x
1000 g --> 2220 g
So : [tex]x = \frac{250*2220}{1000} = \frac{555000}{1000}= 555g [/tex].
In short, 555g of AgNO3 can be dissolved in 250g of water at 20°C.
Hope this helps !
Photon