The acceleration of this object is 5 [tex]m/s^2[/tex].
Given the following data:
- Initial velocity = 0 m/s (since the object starts from rest).
To find the acceleration of the object, we would use the second equation of motion:
Mathematically, the second equation of motion is given by the formula;
[tex]S = ut + \frac{1}{2}at^2[/tex]
Where:
- S represents the distance covered.
- u is the initial velocity.
- a represents the acceleration.
- t is the time measured in seconds.
Substituting the parameters into the formula, we have;
[tex]10 = 0(2) + \frac{1}{2}a(2^2)\\\\10 = \frac{1}{2}a(4)\\\\10 = 2a\\\\a = \frac{10}{2}[/tex]
Acceleration, a = 5 [tex]m/s^2[/tex]
Therefore, the acceleration of this object is 5 [tex]m/s^2[/tex].
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