Answer:
[tex]x=\frac{1+i\sqrt{107} }{6}[/tex]
[tex]x=\frac{1-i\sqrt{107} }{6}[/tex]
Step-by-step explanation:
[tex]3x^2 - x + 9 = 0[/tex]
To solve for x we use quadratic formula
[tex]x=\frac{-b+-\sqrt{b^2-4ac} }{2a}[/tex]
The value of a=3, b=-1 and c=9
Plug in the values in the formula and solve for x
[tex]x=\frac{-b+-\sqrt{b^2-4ac} }{2a}[/tex]
[tex]x=\frac{1+-\sqrt{(-1)^2-4(3)(9)} }{2(3)}[/tex]
[tex]x=\frac{1+-\sqrt{-107} }{6}[/tex]
The value of square root (-1) is 'i'
[tex]x=\frac{1+i\sqrt{107} }{6}[/tex]
[tex]x=\frac{1-i\sqrt{107} }{6}[/tex]
