Answer: C) 75%
Step-by-step explanation:
Let G represents the event of having garbage in houses and F represents the event of houses having fenced in backyard.
Given: In neighborhood , the probability of houses have a garage and a fenced in backyard [tex]P(G\cap F)= 60\%=0.6[/tex]
The probability of houses have a garage P(G)=80%=0.8
The probability that a house has a fenced in backyard given that it has a garage is given by :-
[tex]P(F|G)=\dfrac{P(G\cap F)}{P(G)}\\\\\Rightarrow\ P(F|G)=\dfrac{0.6}{0.8}=0.75[/tex]
In percent, [tex]0.75\times100=75\%[/tex]
Hence, the probability that a house has a fenced in backyard given that it has a garage = 75%.
