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−2x² − 3x + 8
delta = (-3)²-4(-2)(8) =9+64 = 73 ... (delta) > 0
The discriminant is 73, so the equation has 2 real solutions
−2x² − 3x + 8
delta = (-3)²-4(-2)(8) =9+64 = 73 ... (delta) > 0
The discriminant is 73, so the equation has 2 real solutions
Answer:
C. The discriminant is 73, so the equation has 2 real solutions.
Step-by-step explanation:
We have been given an equation [tex]-2x^2-3x+8=0[/tex]. We are asked to determine the number of real solutions for our given equation using discriminant formula.
[tex]D=b^2-4ac[/tex], where,
D = Discriminant,
b = Coefficient of x or middle term.
a = Leading coefficient,
c = constant.
When [tex]D=0[/tex], the equation has two real and equal zeros.
When [tex]D>0[/tex], the equation has two real and distinct zeros.
When [tex]D<0[/tex], the equation has no real zeros.
Upon substituting our given values in above formula we will get,
[tex]D=(-3)^2-4*-2*8[/tex]
[tex]D=9+8*8[/tex]
[tex]D=9+64[/tex]
[tex]D=73[/tex]
Since the value of discriminant is 73 that is greater than 0, therefore, the equation has two real zeros and option C is the correct choice.