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A trampoline has a spring constant of 3430 N/m how far will the trampoline sink when a 70 kg person steps on it

Respuesta :

F = ma = -kx

a = 9.81 m/s²
k = 3430 N/m
m = 70 kg

x = - ma/ k = 0.2m

Answer:

20 cm

Explanation:

Force = mass * acceleration  F = ma (1)

Spring equation is given as Force = Spring constant*Distance (2)

combine 1 & 2

F = ma = Spring constant*Distance

70 * 9.81 = 3430 * d

d = 0.2 m or 20 cm

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