Answer:
Q = 2926 kJ
Explanation:
Given that,
Initial temperature of water, [tex]T_1=0^{\circ}[/tex]
Final temperature of water, [tex]T_2=35^{\circ}[/tex]
Mass, m = 20 kg
To find,
Heat energy required to raise the temperature.
Solution,
Let Q is the heat energy required to raise the temperature. It is based on the concept of specific heat. The expression for the heat raised is given by :
[tex]Q=mc\Delta T[/tex]
c is the specific heat of water, [tex]c=4180\ kJ/kgC[/tex]
[tex]Q=20\times 4180\times (35-0)[/tex]
Q = 2926000 Joules
or
Q = 2926 kJ
So, the heat energy required to raise the temperature of water is 2926 kJ.
