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Jorge is painting a rectangular mural. Its length is 2 ft less than twice its width. Its area is 264 ft^2. Find the dimensions of the mural.

Respuesta :



let w = the width of the rectangle

then, (2w - 2) = the length of the rectangle [Its length is 2 ft less than twice its width]

Area = w(2w - 2) = 2w² - 2w = 264

w² - w - 132 = 0

(w - 12)(w + 11) = 0

w = - 11 [extraneous]
or
w = 12 ft

width = 12 ft, length = 22 ft

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