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The expression x3 – 64 can be written as (x)3 – (4)3. What is the factorization of x3 – 64?
a3 – b3 = (a – b)(a2 + ab + b2)
(x – 4)(x2 + 4x + 8)
(x – 4)(x2 + 4x + 16)
(x – 64)(x2 + 64x + 16)
(x – 64)(x2 + 64x + 4,096)

Respuesta :

adam1299
by factoring x^3-64 put you should get the second option as your answer

(x-4)(x^2+4x+16)
2134jenny

Answer:

[tex](x-4)(x^2+4x+16)[/tex]

Step-by-step explanation:

We have [tex]x^{3}-64=x^3-4^3[/tex] And we know that: [tex]a^3-b^3=(a-b)(a^2+ab+b^2)[/tex]. In our case we have that [tex]a=x[/tex] and [tex]b=4[/tex], then we can eliminate the two last options. And we have:

[tex]x^3-4^3=(x-4)(x^2+x4+4^2)=(x-4)(x^2+4x+16)[/tex]

Then the correct factorization is the second option.

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