we have
[tex]x^{2} -\frac{3}{4}x=5[/tex]
Divide the term [tex]\frac{3}{4}[/tex] by [tex]2[/tex] and then square it
[tex](\frac{(3/4)}{2})^{2}= \frac{9}{64}[/tex]
Add to both sides
[tex]x^{2} -\frac{3}{4}x+\frac{9}{64}=5+\frac{9}{64}[/tex]
Rewrite as perfect square
[tex](x-\frac{3}{8})^{2}=\frac{329}{64}[/tex]
therefore
the answer is
[tex]\frac{9}{64}[/tex]
