Respuesta :
Recall that cosine will always output a value between -1 and 1.
So your f(x) will never be smaller than e^(-1) and never larger than e^(1).
Meanwhile, your g(x) is growing growing growing.
Nothing is slowing it down.
Therefore, g(x) is growing faster than f(x) as x goes to infinity.
So your f(x) will never be smaller than e^(-1) and never larger than e^(1).
Meanwhile, your g(x) is growing growing growing.
Nothing is slowing it down.
Therefore, g(x) is growing faster than f(x) as x goes to infinity.