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The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 18 inches What is the height of the triangular base of the pyramid

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The height of the triangular base of the pyramid is calculated through the equation,
                                        h = (cos x)(18 in)
where h is height and x is half of the angle of the triangle. Since the triangle is equilateral, the value of  x is 30°. Substituting,
                                        h = (cos 30°)(18 in)
                                        h = 15.59 in
Thus, the height of the base is approximately 15.59 inches. 

The height of the triangular base of the pyramid is 15.60 cm

The base of the solid oblique pyramid is an equilateral triangle.

Equilateral triangle

An equilateral triangle are triangle that have all it sides equal to each other.

The height of the triangular base of the pyramid can be found as follows::

The base edges are 18 cm. Therefore,

let

x = half of the angle

Each angle is 60 degrees

cos x = adjacent / hypotenuse

cos 30 = h / 18

h = 18 × 0.86602540378

h = 15.5884572681

h = 15.60 inches

learn more on pyramid here: https://brainly.com/question/3398126

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