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A 1.205 g sample mixture of lithium hydrogen carbonate is decomposed by heating. If they mass loss is 0.275g, what is the percentage of LiHCO3 in the unknown mixture?

Respuesta :

To determine the percent of LiHCO3 in the mixture, we need to calculate for the amount of LiHCO3 by first knowing what really happens in the process. We do as follows:

2 LiHCO3(s) --Heat--> Li2CO3(s) + H2CO3(g)

0.275 g = mass of H2CO3

mass of LiHCO3 = 0.275g (1 mol / 62.03 g) ( 2 mol LiHCO3 / 1 mol H2CO3 ) (67.96 g / 1 mol ) = 0.6026 g LiHCO3

% percent = 0.6026 / 1.205 x 100 = 50%

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