George wishes to increase the percent of acid in 50ml of a 15% acid solution in water to 25% acid, how much pure acid must you add?

amount times concentration=quantity

50(0.15)+x(1)=(50+x)(0.25)
x=amount of acid to add

so
7.5+x=12.5+0.25x
minus 0.25x both sides
7.5+0.75x=12.5
minus 7.5 both sides
0.75x=5
divide both sides by 0.75
x=6.666666666
converts to 6 and 2/3

you have to add 6 and 2/3ml of pure acid

Answer Link

ayfat23 ayfat23 · Answer 2 · 2022-04-25T18:02:35+02:00

[tex]6.67ml[/tex]of pure acid were added to increase the percent of acid in [tex]50ml[/tex]of a 15% acid solution in water to 25% acid.

What is percentage?

A percentage serves as the number or ratio expressed as a fraction of 100.

Let the amount of acid to be added= y

Let the amount of acid to be added= y

50ml of 15% of acid[tex]= 7.5+y[/tex]

But we want to increase to 25% which can be written as [tex]( 50+y)0.25)[/tex]

Since [tex]Quantity of acid=( concentration of the acid* amount of the acid)[/tex]

Then[tex]( 50+y)0.25= 7.5+y)[/tex]

collect the like terms

[tex]12.5+0.25y= 7.5+y[/tex]

5= 0.75y

[tex]= 6.67ml of pure acid[/tex]

Therefore, 6.67ml of pure acid were added.

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