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The base-dissociation constant, kb, for pyridine, c5h5n, is 1.4x10-9 the acid-dissociation constant, ka, for the pyridinium ion, (pyridine's conjugate acid, is __________.

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BlueSky06
We are given the base dissociation constant, Kb, for Pyridine (C5H5N) which is 1.4x10^-9. The acid dissociation constant, Ka for the Pyridium ion or the conjugate acid of Pyridine is to be determined. We know from our chemistry classes that:

Kw = Kb * Ka

where Kw is always equal to 1x10^-14

so, to solve for Ka of Pyridium ion, substitute Kb to the equation together with Kw and solve for Ka:

1x10^-14 = 1.4x10^-9 * Ka
solve for Ka

Ka = 7.14x10^-6 

Therefore, the acid dissociation constant of Pyridinium ion is 7.14x10^-6.

The value of an acid dissociation constant for the pyridinium ion, which is a pyridine's conjugate acid is 7.14x10⁻⁶.

How we calculate acid dissociation constant?

Acid dissociation constant will be calculated as:
Kw = Ka × Kb, where

Kw = dissociation constant of water = 10⁻¹⁴

Kb = base dissociation constant for pyridine = 1.4 × 10⁻⁹

Ka is an acid dissociation constant will be calculated as:
Ka = Kw / Kb

On putting these values on the above equation, we get:
Ka = 10⁻¹⁴ / 1.4 × 10⁻⁹

Ka = 7.14x10⁻⁶

Hence, 7.14x10⁻⁶ is the value of Ka.

To know more about acid dissociation constant, visit the below link:
https://brainly.com/question/26998

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