CalendarDevelopmental Math An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment. Compute the probability of each of the following events: Event A : The sum is greater than 7 . Event B : The sum is divisible by 6 . Write your answers as exact fractions.

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joaobezerra joaobezerra · Answer 1 · 2022-03-02T09:52:15+01:00

Using the it's concept, it is found that the probabilities are of:

A. 0.4167 = 41.67%

B. 0.1667 = 16.67%

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, two dice are rolled, each with 6 outcomes, hence there are 36 possible outcomes, which are:

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

Item a:

Of those, 15 have a sum greater than 8, hence:

[tex]p = \frac{15}{36} = 0.4167[/tex]

Item b:

6 outcomes have a sum divisible by 6, hence:

[tex]p = \frac{6}{36} = 0.1667[/tex]

More can be learned about probabilities at https://brainly.com/question/15536019