contestada

if 0.50 L of a 5.00 M stock solution of HCL is diluted to make 2.0 L of solution, how much HCL, in grams, is in the solution?

Respuesta :

JavierCollante
the number of moles does not change when you dilute a solution. if you find the moles in the original solution, should be the same amount of moles in the diluted solution. 

mole HCl= (0.50 L) x (5.00M)= 2.50 moles HCl

use the molar mass to change moles to grams

2.50 mole HCl (36.51 grams/ 1 mole)= 91.3 grams HCl

The mass of HCl, in grams, present in the solution is 91.15 g

From the question,

We are to determine the mass of HCl, in grams, present in the solution

First, we will determine the number of moles of HCl in 0.50 L of the 5.00 M stock solution,

Concentration = 5.00 M

Volume = 0.50 L

From the formula

Number of moles = Concentration × Volume

∴ Number of moles of HCl present = 5.00 × 0.50

Number of moles of HCl present = 2.50 moles

Now, for the mass in grams, of HCl

Using the formula

Mass = Number of moles × Molar mass

Molar mass of HCl = 36.46 g/mol

∴ Mass of HCl present in the solution = 2.50 × 36.46

Mass of HCl present in the solution = 91.15 g

Hence, the mass of HCl, in grams, present in the solution is 91.15 g

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