Answer:
35 possible combinations would be there.
Step-by-step explanation:
We have total of seven students we have to choose three out of those seven
[tex]^{n}C_r=\frac{n!}{r!\cdot (n-r)!}[/tex]
n is the total possibilities n =7 in the given case
And r is the chosen ones
Hence, r=3 in the given case.
Substituting the values of n and r in the formula we get
[tex]^{7}C_3[/tex]
[tex]\frac{7!}{3!(7-3)!}[/tex]
[tex]\frac{7!}{3!\cdot 4!}[/tex]
Using n!=n(n-1)----1
[tex]\frac{7\cdot 6\cdot 5\cdot 4!}{3\cdot 2\cdot 1\cdot 4!}[/tex]
Cancel the common factor we get
[tex]35[/tex] possible combinations would be there.
