A parking space shaped like a parallelogram has a base of 17 feet and s height is 9 feet. A car parked in the space is 16 feet long and 6 feet wide. How much of the parking space is not covered by the car?

We know that the whole area of the parking space is 17 by 9. That is equal to 153 feet. The covered space is 16 by 6. That is equal to 96 feet. 153-96=57. There are 57 feet that are not covered by the car.

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PsychrolutesMarcidus PsychrolutesMarcidus · Answer 2 · 2017-05-07T01:57:21+02:00

By subtracting the area of the car from the area of the parking space we can find the non-occupied area.

[tex] A_{free}= A_{space}- A_{space} [/tex]

But the area of the car, and space must be found first

Knowing the space is a parallelogram, we can use the formula A=bh.
The area of a parallelogram is base(height)

[tex] A_{space}= base(height) [/tex]
[tex] A_{space}= 17(9) [/tex]
[tex] A_{space}= 17(9) [/tex]
[tex] A_{space}= 153 ft^2[/tex]

By multiplying the width and length of the car we can find the car's area.

[tex] A_{car}= width(lenght)[/tex]
[tex] A_{car}= 6(16)[/tex]
[tex] A_{car}= 96 ft^2[/tex]

With the first formula written and the value of the area, we can find the free space
[tex] A_{free}= A_{space}- A_{space} [/tex]
[tex] A_{free}= 153- 96[/tex]
[tex]A_{free}= 57ft^2[/tex]

The space not occupied is 57 ft²