Respuesta :

egoodrich1337
In order to solve this, we need to select the function that meets our constraints. Since x^2 - 5 occurs when x is less than 3, and the x-value we are given is -4, we use the first function.

f(-4) = (-4)^2 - 5
f(-4) = 16 - 5
f(-4) = 11

Answer:

Answer is 11

Step-by-step explanation:

Given in a piecewise function as

[tex]f(x) = x^2-5, x<3\\f(x) = 2x^2+5,x>3[/tex]

We find that the above function is defined for all real values of x except at x =3

We are to find out f(-4)

Since [tex]-4<3,[/tex] we substitute -4 in the first function

[tex]f(-4) = (-4)^2-5= 11[/tex]

Thus we get answer as 11

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