"The sum of the squares of the digits is 26"
10t + u = 26 ---->(1)
"If the number is decreased by the number with its digits reversed, the result is 36"
u - 10t =36 -----> (2)
By subtracting the equation we can find t.
u+10t = 26)
-(u-10t=36)
______________
0u +20t = 26 -36
---> 20t = -10
t= -10/20
t= -1/2
Inserting value t in (1)
10t + u = 26
10(-1/2) + u= 26
-5+u=26
u= 26+5 = 31
Using u and t in the original expression 10t+u express a positive number
10t+u
= 10(-1/2) +u
= -5 + 31
= 26
----> Proves this statement is true
"The sum of the squares of the digits is 26"
10t + u = 26
