Respuesta :
We are given:
138 km south
83 km west of the bearing is the drop-off point.
First, we need to illustrate the problem to clearly see the pattern.
A triangle is formed, 138 km down, then 83 km left.
c^2 = 138^2 + 83^2
c = 161.04 km
The angles are determined using Pythagorean Theorem:
a) 217 degrees
b) 31 degrees
138 km south
83 km west of the bearing is the drop-off point.
First, we need to illustrate the problem to clearly see the pattern.
A triangle is formed, 138 km down, then 83 km left.
c^2 = 138^2 + 83^2
c = 161.04 km
The angles are determined using Pythagorean Theorem:
a) 217 degrees
b) 31 degrees
Answer:
A) the drop-off point from the air base : 31° towards South West
B) the air base from the drop-off point : 59° towards North East
Step-by-step explanation:
Please refer to the image attached to the answer. Here we see that the Air base , The drop-off point and the south direction makes an right angle Triangle.
We are asked to find the angles x and y as shown in the figure. We use trigonometric ratios to determine them.
We know that in a right Triangle
[tex]\tan \theta=\frac{opposite}{adjacent}[/tex]
Hence
[tex]\tan x=\frac{83}{138}[/tex]
[tex]\tan x = 0.60[/tex]
[tex]x=\tan^{-1} (0.60)[/tex]
Using calculator
[tex]x=30.96[/tex]
[tex]x=31[/tex] Approximately
Also the sum of all the angles in a right triangle is 90°. hence
[tex]y=180-90-31[/tex]
[tex]y=59[/tex]
hence we have our x and y as 31° and 59°
