An aeroplane flies 138 km in a southerly direction from a military air base to a drop-off point The drop-off point is 83 km west of the the bearing, correct to the nearest air base. Find degree, of:
A) the drop-off point from the air base
B) the air base from the drop-off point.

Respuesta :

We are given: 

138 km south 
83 km west of the bearing is the drop-off point.

First, we need to illustrate the problem to clearly see the pattern.

A triangle is formed, 138 km down, then 83 km left. 

c^2 = 138^2 + 83^2 
c = 161.04 km

The angles are determined using Pythagorean Theorem:

a) 217 degrees 
b) 31 degrees

Answer:

A) the drop-off point from the air base : 31°  towards South West

B) the air base from the drop-off point : 59° towards North East

Step-by-step explanation:

Please refer to the image attached to the answer. Here we see that the Air base , The drop-off point and the south direction makes an right angle Triangle.

We are asked to find the angles x and y as shown in the figure. We use trigonometric ratios to determine them.

We know that in a right Triangle

[tex]\tan \theta=\frac{opposite}{adjacent}[/tex]

Hence

[tex]\tan x=\frac{83}{138}[/tex]

[tex]\tan x = 0.60[/tex]

[tex]x=\tan^{-1} (0.60)[/tex]

Using calculator

[tex]x=30.96[/tex]

[tex]x=31[/tex] Approximately

Also the sum of all the angles in a right triangle is 90°. hence

[tex]y=180-90-31[/tex]

[tex]y=59[/tex]

hence we have our x and y as 31° and 59°  

Ver imagen Cricetus