A principal of $3800 is invested at 3% interest, compounded annually. How much will the investment be worth after
10 years?
Use the calculator provided and round your answer to the nearest dollar.

Respuesta :

Total = Principal * (1 + rate)^years
Total = 3,800 * (1.03) ^ 10
Total = 3,800 * 1.3439163793
Total = 5,106.88



The investment be worth after 10 years on compounded annually is $5107.

What is compound interest?

Compound interest is the interest you earn on interest. Compound interest is the interest calculated on the principal and the interest accumulated over the previous period.

For the given situation,

Principal, p = $3800

Rate of interest, r = 3% = 0.03

Annually, n = 1

Time period, t = 10 years

The formula of amount in compound interest is

[tex]A = p(1+\frac{r}{n} )^{nT}[/tex]

On substituting the above values,

⇒ [tex]A = 3800(1+\frac{0.03}{1} )^{1(10)}[/tex]

⇒ [tex]A = 3800(1+0.03 )^{10}[/tex]

⇒ [tex]A = 3800(1.03 )^{10}[/tex]

⇒ [tex]A = 3800(1.3439)[/tex]

⇒ [tex]A=5106.88[/tex] ≈ [tex]5107[/tex]

Hence we can conclude that the investment be worth after 10 years on compounded annually is $5107.

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