kendramadison20
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Complete the proof to show that ABCD is a parallelogram.






The slope of BC is . The slope of AD is . The slope of CD is . The slope of BA is . BC ∥ AD and CD ∥ BA because the . Therefore, ABCD is a parallelogram because both pairs of opposite sides are parallel.

Complete the proof to show that ABCD is a parallelogramThe slope of BC is The slope of AD is The slope of CD is The slope of BA is BC AD and CD BA because the T class=

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meerkat18
The slope of BC is
(4-2)/(-3-2) = -2/5

The slope of AD is 
(-2- -4)/(-2-3) = -2/5

The slope of CD is
(2- -4)/(2-3) = -6

The slope of BA is
(4- -2)/(-3- -2) = -6
 
BC ∥ AD and CD ∥ BA because their slopes are equal. Therefore, ABCD is a parallelogram because both pairs of opposite sides are parallel.
ankitprmr2

If the opposite sides of any quadrilateral are parallel to each other, then the quadrilateral is entitled to a parallelogram. Thus, ABCD is a parallelogram.

The question is asked to prove the quadrilateral ABCD a parallelogram.

Now, If the opposite sides of any quadrilateral are parallel to each other, then the quadrilateral is entitled to a parallelogram. If the slope of lines is congruent to each other then the lines are parallel.

The formula for finding the slope of a line from the given coordinates [tex](x_1,y_1)[/tex] and [tex](x_2, y_2)[/tex] is mentioned below:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

Therefore,

  • The slope of AB is -6.

  • The slope of BC is -2/5.

  • The slope of CD is -6.

  • The slope of AD is -2/5.

Now, the slope of AB is congruent to the slope of CD, and the slope of BC is congruent to the slope of AD.

Hence,

[tex]AB \parallel CD\\BC \parallel AD[/tex]

Thus, ABCD is a parallelogram.

To know more about the parallelograms, please refer to the link:

https://brainly.com/question/9680084

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