Bubbles98
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an internet password consists of a digit followed by a letter,followed by another digit,assuming the digits are 0-9.how many different passcode are possible?

Respuesta :

JeanaShupp

Answer: 2,600

Step-by-step explanation:

Given: The total number choices of digits (0-9) for the first and the third place of  internet password= 10

The total number of choices for letters for the middle place of internet password (Number of letters in English alphabet)= 26

Now, the number of different internet passcode are possible is given by :-

[tex]10\times26\times10=2,600[/tex]

Hence, the  number of different internet passcode are possible = 2,600.

facundo3141592

We will see that there are 2,600 different passwords.

How to find the total number of combinations?

First, we need to define the selections, these are:

  • First digit.
  • First letter.
  • Second digit.

Now we need to find the number of options for each one of these selections, for the digits we have 10 options, and for the letter we have 26 options.

Then:

  • First digit: 10 options.
  • First letter: 26 options.
  • Second digit: 10 options.

The total number of combinations is given by the product between these numbers of options, we have:

C = 10*26*10 = 2,600

So there are 2,600 different passwords.

If you want to learn more about combinations, you can read:

https://brainly.com/question/2280026

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