Respuesta :

padawan
m∠CBD = 60°
BD = BC = 10 (radius)
m∠BCD = m∠BDC = 60°
equilateral triangle
CD = BC = 10

m∠CAD = 90°
AD = AC (radius)
m∠ACD = m∠ADC = 60°
AC = CDsin(45) ; pythagorus
= 10/sqrt(2) = 5sqrt(2)

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