Respuesta :
hello :
13π/4 = (16-3)π/4
= 16π/4 -3π/4
13π/4 = -3π/4 +4π
tan( 13π/4) = tan ( -3π/4)= - tan ( 3π/4) =- tan( π - π/4) = - tan(- π/4)
tan( 13π/4) = -(-tan(π/4)) =tan(π/4)=1
13π/4 = (16-3)π/4
= 16π/4 -3π/4
13π/4 = -3π/4 +4π
tan( 13π/4) = tan ( -3π/4)= - tan ( 3π/4) =- tan( π - π/4) = - tan(- π/4)
tan( 13π/4) = -(-tan(π/4)) =tan(π/4)=1
Answer:
1
Step-by-step explanation:
Tan 13π/4 = tan(3π + 1/4π)
According to the trigonometry identity;
tan(A+B) = tanA + tanB/1-tanAtanB
If A = 3π and B = π/4
tan(3π + 1/4π) = tan 3π + tanπ/4/1-tan3πtanπ/4
If πrad = 180°
tan(3π + 1/4π) = tan 540° + tan45°/1-tan540°tan45°
tan(3π + 1/4π) = 0+1/1-0(1)
tan(3π + 1/4π) = 1/1-0
tan(3π + 1/4π) = 1/1
tan(3π + 1/4π) = 1
tan 13π/4 = 1