a bag contains 30 lottery balls numbered 1-30 a ball is selected, not replaced,then another is drawn.find each probability
p (a 2 - digit number, then 4)
p (19,then a multiple of 4)
p (24,then a number less then 15)
p (two perfect squares)

Respuesta :

The probability of the first event with x possible outcomes is equal to x/30. Also, the probability of the second event with y possible outcomes is y/29.

(1) P of 2 digit number, 21/30
      P that the number is 4 is 1/29
Multiplying both probabilities will give us 7/290

(2) P that number is 19 is 1/30
      P that the number is multiple by 4 is 6/29
The answer is 1/145

(3) P that number is 24 is 1/30
      P that number is less than 15 is 14/29
The answer should be 7/435.

(4) P that number 1st number is perfect square is 5/30
   P that second number is perfect square is 4/29.
The answer is 2/87. 

The values of the probabilities are:

p (a 2 - digit number, then 4) =  1/870

p (19,then a multiple of 4) =  7 /870

p (24,then a number less then 15) = 42 / 87

p (two perfect squares) = 2/87

What are the probabilities?

Probabilities are used to determine the chances that a random event would occur.

p (a 2 - digit number, then 4) = (number of 2s / total numbers) x (number of 4 / total numbers) = 1/30 x 1/29 = 1/870

p (19,then a multiple of 4) = (number of 19s / total numbers) x (total multiple of 4 / total numbers)

1/30 x 7/29 = 7/870

p (24,then a number less then 15) = (number of 19s / total numbers) x (total numbers less than 24 / total numbers)

1/30 x 14/29 = 42 / 87

p (two perfect squares) = (total number of perfect squares / total numbers) x (total number of perfect squares / total numbers- 1)

(5/30) x (4/29) = 2/87

To learn more about probability, please check: https://brainly.com/question/13234031

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