catniklau
contestada

The center of a circle is at (2, −5) and its radius is 12.

What is the equation of the circle?


a) (x−2)2+(y+5)2=24

b) (x+2)2+(y−5)2=24

c) (x+2)2+(y−5)2=144

d) (x−2)2+(y+5)2=144

Respuesta :

ghanami
hello :
an equation of the circle Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =2 and b = -5 (Center at the A) and: r = 12
the equation of the circle is : (x-2)² +(y+5)² = 12²=144 (answer d)

The equation of the circle is [tex](x-2)^2+(y+5)^2=144[/tex]. So, option d is correct.

Given:

The center of the circle is [tex](2,-5)[/tex] and the radius is [tex]12[/tex].

To find:

The equation of the circle.

Explanation:

The standard form of a circle is:

[tex](x-h)^2+(y-k)^2=r^2[/tex]        ...(i)

Where, [tex](h,k)[/tex] is center and [tex]r[/tex] is the radius.

Substitute [tex]h=2,k=-5,r=12[/tex] in (i).

[tex](x-2)^2+(y-(-5))^2=(12)^2[/tex]

[tex](x-2)^2+(y+5)^2=144[/tex]

Therefore, the correct option is d.

Learn more:

https://brainly.com/question/12981520

Ver imagen erinna

Otras preguntas