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A young's interference experiment is performed with blue-green laser light. the separation between the slits is 0.500 mm, and the screen is located 3.14 m from the slits. the first bright fringe is located 3.32 mm from the center of the interference pattern. what is the wavelength of the laser light?

Respuesta :

egenriether
Use the relation  dsin(θ) = mλ
Your angle is given by θ=tan⁻¹(3.32e-3/3.14) = 0.06058 degrees
λ = dsin(θ)/m = (0.5e-3)(0.001057)/1  (use 1 in denominator since its the first order maximum)
λ = 5.2866e-7  Or  λ = 528.66nm

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